{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu","formal_name":"MMLU","introduction":"MMLU asks four-way multiple-choice questions across 57 subjects, from elementary material to professional-level examinations. Since 2020 it has been the most widely cited single reference point for general capability.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://github.com/hendrycks/test","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"01f05203-3dac-5b6e-ba6d-6baef1c87b1a","task_key":"all--test--01f05203-3dac-5b6e-ba6d-6baef1c87b1a","task_revision_id":"1","upstream_id":"","short_description":"PCl3(g) + Cl2(g) ↔ PCl5(g) ΔH = -92.5 kJ/mol In which of the following ways…","config":"all","split":"test","body":"{\"choices\":\"['Decreasing the concentration of PCl3', 'Increasing the pressure', 'Increasing the temperature', 'None of the above']\",\"question\":\"PCl3(g) + Cl2(g) ↔ PCl5(g) ΔH = -92.5 kJ/mol In which of the following ways could the reaction above be manipulated to create more product?\",\"subject\":\"high_school_chemistry\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://github.com/hendrycks/test","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}