{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"omni-math","formal_name":"Omni-MATH","introduction":"Omni-MATH evaluates mathematical reasoning on Olympiad-level problems. Its official dataset contains 4,428 problems accompanied by domain and difficulty information.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"027a8263-dca2-54b4-92d0-5a0cfef21df3","task_key":"test--027a8263-dca2-54b4-92d0-5a0cfef21df3","task_revision_id":"1","upstream_id":"","short_description":"Let $ABC$ be a triangle with $\\angle A = 90^{\\circ}$. Points $D$ and $E$ lie on…","config":"","split":"test","body":"{\"problem\":\"Let $ABC$ be a triangle with $\\\\angle A = 90^{\\\\circ}$. Points $D$ and $E$ lie on sides $AC$ and $AB$, respectively, such that $\\\\angle ABD = \\\\angle DBC$ and $\\\\angle ACE = \\\\angle ECB$. Segments $BD$ and $CE$ meet at $I$. Determine whether or not it is possible for segments $AB$, $AC$, $BI$, $ID$, $CI$, $IE$ to all have integer lengths.\"}","display_format":"math","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}