{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"0b34b4c2-4e9f-554b-a927-beac63d019c9","task_key":"default--test--3964","task_revision_id":"1","upstream_id":"3964","short_description":"At a constant pressure and a temperature of - 10°C, water freezes. Calculate the…","config":"default","split":"test","body":"{\"category\":\"chemistry\",\"options\":\"['- 70.4 cal g^-1', '- 73.1 cal g^-1', '- 79.7 cal g^-1', '- 80.2 cal g^-1', '- 77.9 cal g^-1', '- 69.0 cal g^-1', '- 76.5 cal g^-1', '- 82.3 cal g^-1', '- 75.2 cal g^-1', '- 74.6 cal g^-1']\",\"question\":\"At a constant pressure and a temperature of - 10°C, water freezes. Calculate the heat evolved in the process. H_2O(l) = H_2O (s) Given the following: \\\\DeltaH_273 = - 79.7 cal g^-1 CP, -(H)2 O (l)= 1.00 cal K^-1 g^-1 and CP, (H)2 O(s)= 0.49 cal K^-1g^-1\",\"src\":\"stemez-PhysicalChemistry\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}