{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"0faa4be7-f3d7-5a01-a1f6-bb0d7380deae","task_key":"default--test--4067","task_revision_id":"1","upstream_id":"4067","short_description":"A heat pump with a coefficient of performance given by COP = - (q_1 / w) = [T_1…","config":"default","split":"test","body":"{\"category\":\"chemistry\",\"options\":\"['6.0', '11.0', '8.5', '10.0', '5.0', '9.0', '7.5', '8.0', '7.0', '4.0']\",\"question\":\"A heat pump with a coefficient of performance given by COP = - (q_1 / w) = [T_1 / (T_2 - T_1)] = 7.0 is used to pump an amount of heat q_1 at a temperature T_1, from the cold outdoors to the interior of a house at a temperature T_2. Calculate (q_2 / w), the ratio of the heat liberated at the higher temperature T_2 to the work done.\",\"src\":\"stemez-PhysicalChemistry\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}