{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"omni-math","formal_name":"Omni-MATH","introduction":"Omni-MATH evaluates mathematical reasoning on Olympiad-level problems. Its official dataset contains 4,428 problems accompanied by domain and difficulty information.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"12618390-0b60-5cb5-aafa-b03d8c2d414c","task_key":"test--12618390-0b60-5cb5-aafa-b03d8c2d414c","task_revision_id":"1","upstream_id":"","short_description":"Let $\\zeta=e^{2 \\pi i / 99}$ and $\\omega=e^{2 \\pi i / 101}$. The polynomial…","config":"","split":"test","body":"{\"problem\":\"Let $\\\\zeta=e^{2 \\\\pi i / 99}$ and $\\\\omega=e^{2 \\\\pi i / 101}$. The polynomial $$x^{9999}+a_{9998} x^{9998}+\\\\cdots+a_{1} x+a_{0}$$ has roots $\\\\zeta^{m}+\\\\omega^{n}$ for all pairs of integers $(m, n)$ with $0 \\\\leq m<99$ and $0 \\\\leq n<101$. Compute $a_{9799}+a_{9800}+\\\\cdots+a_{9998}$.\"}","display_format":"math","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}