{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"omni-math","formal_name":"Omni-MATH","introduction":"Omni-MATH evaluates mathematical reasoning on Olympiad-level problems. Its official dataset contains 4,428 problems accompanied by domain and difficulty information.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"16a42dd6-39c9-5de5-ba36-e629b3506804","task_key":"test--16a42dd6-39c9-5de5-ba36-e629b3506804","task_revision_id":"1","upstream_id":"","short_description":"Triangle $A B C$ obeys $A B=2 A C$ and $\\angle B A C=120^{\\circ}$. Points $P$…","config":"","split":"test","body":"{\"problem\":\"Triangle $A B C$ obeys $A B=2 A C$ and $\\\\angle B A C=120^{\\\\circ}$. Points $P$ and $Q$ lie on segment $B C$ such that $$\\\\begin{aligned} A B^{2}+B C \\\\cdot C P & =B C^{2} \\\\\\\\ 3 A C^{2}+2 B C \\\\cdot C Q & =B C^{2} \\\\end{aligned}$$ Find $\\\\angle P A Q$ in degrees.\"}","display_format":"math","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}