{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"omni-math","formal_name":"Omni-MATH","introduction":"Omni-MATH evaluates mathematical reasoning on Olympiad-level problems. Its official dataset contains 4,428 problems accompanied by domain and difficulty information.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"174a18ba-4d70-51c6-b87b-ded0c63ac72f","task_key":"test--174a18ba-4d70-51c6-b87b-ded0c63ac72f","task_revision_id":"1","upstream_id":"","short_description":"Estimate $N=\\prod_{n=1}^{\\infty} n^{n^{-1.25}}$. An estimate of $E>0$ will…","config":"","split":"test","body":"{\"problem\":\"Estimate $N=\\\\prod_{n=1}^{\\\\infty} n^{n^{-1.25}}$. An estimate of $E>0$ will receive $\\\\lfloor 22 \\\\min (N / E, E / N)\\\\rfloor$ points.\"}","display_format":"math","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}