{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"19e1ebd4-5caf-50ac-a12a-301ae19188ff","task_key":"default--test--3676","task_revision_id":"1","upstream_id":"3676","short_description":"Chlorine may be prepared by the action of KClO_3 on HCl, and the reaction may be…","config":"default","split":"test","body":"{\"category\":\"chemistry\",\"options\":\"['2.75 g', '1.50 g', '3.00 g', '0.92 g', '2.50 g', '1.00 g', '1.20 g', '2.10 g', '3.68 g', '1.84 g']\",\"question\":\"Chlorine may be prepared by the action of KClO_3 on HCl, and the reaction may be represented by the equation: KClO_3 + 6HCl \\\\rightarrow KCl + 3Cl_2 + 3H_2 O Calculate the weight of KClO_3 which would be required to produce 1.0 liter of Cl_2 gas at STP. R = .082 liter-atm/mole -°K.\",\"src\":\"stemez-Chemistry\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}