{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"omni-math","formal_name":"Omni-MATH","introduction":"Omni-MATH evaluates mathematical reasoning on Olympiad-level problems. Its official dataset contains 4,428 problems accompanied by domain and difficulty information.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"213f0043-3e5d-54e9-b80c-6a6f13693ebf","task_key":"test--213f0043-3e5d-54e9-b80c-6a6f13693ebf","task_revision_id":"1","upstream_id":"","short_description":"Triangle $ABC$ obeys $AB=2AC$ and $\\angle BAC=120^{\\circ}$. Points $P$ and $Q$…","config":"","split":"test","body":"{\"problem\":\"Triangle $ABC$ obeys $AB=2AC$ and $\\\\angle BAC=120^{\\\\circ}$. Points $P$ and $Q$ lie on segment $BC$ such that $$\\\\begin{aligned} AB^{2}+BC \\\\cdot CP & =BC^{2} \\\\\\\\ 3AC^{2}+2BC \\\\cdot CQ & =BC^{2} \\\\end{aligned}$$ Find $\\\\angle PAQ$ in degrees.\"}","display_format":"math","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}