{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"scicode","formal_name":"SciCode","introduction":"SciCode evaluates the ability to solve scientific research problems through code. Problems are decomposed into subproblems; this dev import preserves the relationships between 15 parent problems and 50 subproblems.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/SciCode1/SciCode","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"24044c3f-7e00-58f3-a2fc-7add4bde1661","task_key":"dev--69e335f0-d1ca-5a82-bab6-b343e9761c03--10~2e7","task_revision_id":"2","upstream_id":"10.7","short_description":"Write a Python function to calculate the following weight at each reciprocal…","config":"","split":"dev","body":"{\"step_background\":\"\",\"step_description_prompt\":\"Write a Python function to calculate the following weight at each reciprocal space point. Return only points and weights that are larger than tolerance `tol` (fixed to 1e-10). Inputs are `gpoints_all`, `cell_volume`, `alpha`, `tol`.\\n\\n\\\\begin{align}\\nW(k) &= \\\\frac{4 \\\\pi}{V} \\\\frac{\\\\mathrm{e}^{-\\\\frac{k^2}{4 \\\\alpha^2}}}{k^2} \\n\\\\end{align}\"}","display_format":"scicode-step","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/SciCode1/SciCode","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}