{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"humaneval-plus","formal_name":"HumanEval+","introduction":"HumanEval+ keeps the 164 original HumanEval problems and multiplies their tests by roughly 80×. It exists because the original suite was loose enough to pass implementations that were actually wrong.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://github.com/evalplus/evalplus","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"2427547c-ede3-5d7b-b313-a36e98bdfba8","task_key":"default--test--2427547c-ede3-5d7b-b313-a36e98bdfba8","task_revision_id":"2","upstream_id":"","short_description":"def sort_even(l: list):","config":"default","split":"test","body":"{\"entry_point\":\"sort_even\",\"prompt\":\"\\n\\ndef sort_even(l: list):\\n    \\\"\\\"\\\"This function takes a list l and returns a list l' such that\\n    l' is identical to l in the odd indicies, while its values at the even indicies are equal\\n    to the values of the even indicies of l, but sorted.\\n    >>> sort_even([1, 2, 3])\\n    [1, 2, 3]\\n    >>> sort_even([5, 6, 3, 4])\\n    [3, 6, 5, 4]\\n    \\\"\\\"\\\"\\n\"}","display_format":"code","language":"","answer_status":"published","assets":[],"source_url":"https://github.com/evalplus/evalplus","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}