{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"287a8af3-5407-5c70-8a45-fd9c645ffc57","task_key":"default--test--9262","task_revision_id":"1","upstream_id":"9262","short_description":"The second cosmic velocity (or escape velocity) is the speed required by an…","config":"default","split":"test","body":"{\"category\":\"physics\",\"options\":\"['v = 2sqrt(GM/R)', 'v = sqrt(GM/2R)', 'v = sqrt(2GM/R)', 'v = sqrt(GM*R)', 'v = sqrt(GM/R)', 'v = sqrt(GM)', 'v = 2GM/R', 'v = sqrt(GM/2)', 'v = 2sqrt(2GM/R)', 'v = sqrt(2GM)']\",\"question\":\"The second cosmic velocity (or escape velocity) is the speed required by an object to escape the gravitational field of a celestial body with mass M and radius R. Which formula correctly calculates this velocity? (G: gravitational constant)\",\"src\":\"ori_mmlu-astronomy\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}