{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"cruxeval","formal_name":"CRUXEval","introduction":"CRUXEval takes 800 short Python functions and asks either for the output given an input (CRUXEval-O) or for an input that produces a given output (CRUXEval-I). It measures the ability to execute code mentally rather than to write it.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://crux-eval.github.io/","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"29995106-46ac-5914-b6ab-70032ebbaf8c","task_key":"default--test--sample~5f137","task_revision_id":"2","upstream_id":"sample_137","short_description":"[3, 2, 0, 0, 2, 3]","config":"default","split":"test","body":"{\"code\":\"def f(nums):\\n    count = 0\\n    for i in range(len(nums)):\\n        if len(nums) == 0:\\n            break\\n        if count % 2 == 0:\\n            nums.pop()\\n        else:\\n            nums.pop(0)\\n        count += 1\\n    return nums\",\"input\":\"[3, 2, 0, 0, 2, 3]\"}","display_format":"code","language":"","answer_status":"published","assets":[],"source_url":"https://crux-eval.github.io/","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}