{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"humaneval-plus","formal_name":"HumanEval+","introduction":"HumanEval+ keeps the 164 original HumanEval problems and multiplies their tests by roughly 80×. It exists because the original suite was loose enough to pass implementations that were actually wrong.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://github.com/evalplus/evalplus","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"3de02a17-bcee-5993-993a-dd3d1a9edd45","task_key":"default--test--3de02a17-bcee-5993-993a-dd3d1a9edd45","task_revision_id":"2","upstream_id":"","short_description":"def odd_count(lst):","config":"default","split":"test","body":"{\"entry_point\":\"odd_count\",\"prompt\":\"\\ndef odd_count(lst):\\n    \\\"\\\"\\\"Given a list of strings, where each string consists of only digits, return a list.\\n    Each element i of the output should be \\\"the number of odd elements in the\\n    string i of the input.\\\" where all the i's should be replaced by the number\\n    of odd digits in the i'th string of the input.\\n\\n    >>> odd_count(['1234567'])\\n    [\\\"the number of odd elements 4n the str4ng 4 of the 4nput.\\\"]\\n    >>> odd_count(['3',\\\"11111111\\\"])\\n    [\\\"the number of odd elements 1n the str1ng 1 of the 1nput.\\\",\\n     \\\"the number of odd elements 8n the str8ng 8 of the 8nput.\\\"]\\n    \\\"\\\"\\\"\\n\"}","display_format":"code","language":"","answer_status":"published","assets":[],"source_url":"https://github.com/evalplus/evalplus","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}