{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"4107a6d3-36b8-5dff-931a-16c3373ef62b","task_key":"default--test--4585","task_revision_id":"1","upstream_id":"4585","short_description":"The escape velocity, the speed at which molecules can escape the earth's…","config":"default","split":"test","body":"{\"category\":\"chemistry\",\"options\":\"['1.50 × 10^4 K', '1.20 × 10^4 K', '9.72 × 10^3 K', '3.00 × 10^5 K', '6.50 × 10^3 K', '1.1 × 10^6 K', '5.00 × 10^3 K', '7.50 × 10^3 K', '2.42 × 10^12 K', '2.42 × 10^12 deg']\",\"question\":\"The escape velocity, the speed at which molecules can escape the earth's gravitational field, is approximately 1.1 × 10^6 cm sec^-1 (about 7 miles sec^-1). At what temperature, approximately, will the root mean square velocity value for H_2 be equal to the escape velocity? (R = 8.3 × 10^7 erg mole^-1 deg^-1 ; at. wt: H = 1)\",\"src\":\"stemez-PhysicalChemistry\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}