{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu","formal_name":"MMLU","introduction":"MMLU asks four-way multiple-choice questions across 57 subjects, from elementary material to professional-level examinations. Since 2020 it has been the most widely cited single reference point for general capability.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://github.com/hendrycks/test","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"45b19ded-e453-59a8-b474-75f8697e7ae5","task_key":"all--test--45b19ded-e453-59a8-b474-75f8697e7ae5","task_revision_id":"1","upstream_id":"","short_description":"Statement 1 | A factor group of a non-Abelian group is non-Abelian. Statement 2…","config":"all","split":"test","body":"{\"choices\":\"['True, True', 'False, False', 'True, False', 'False, True']\",\"question\":\"Statement 1 | A factor group of a non-Abelian group is non-Abelian. Statement 2 | If K is a normal subgroup of H and H is a normal subgroup of G, then K is a normal subgroup of G.\",\"subject\":\"abstract_algebra\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://github.com/hendrycks/test","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}