{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"4acda9a8-75fd-5faf-b64d-e315101fbd25","task_key":"default--test--4052","task_revision_id":"1","upstream_id":"4052","short_description":"Calculate \\DeltaE for the proposed basis of an absolutely clean source of…","config":"default","split":"test","body":"{\"category\":\"chemistry\",\"options\":\"['1.01 × 10^8 kcal per mole', '3.02 × 10^7 kcal per mole', '- 2.20 × 10^8 kcal per mole', '- 3.02 × 10^8 kcal per mole', '- 2.01 × 10^8 kcal per mole', '- 2.10 × 10^8 kcal per mole', '2.01 × 10^8 kcal per mole', '- 2.01 × 10^7 kcal per mole', '- 1.01 × 10^7 kcal per mole', '2.01 × 10^7 kcal per mole']\",\"question\":\"Calculate \\\\DeltaE for the proposed basis of an absolutely clean source of nuclear energy (^11 _5)B + (^1 _1)H \\\\rightarrow (^12 _6)C \\\\rightarrow 3 (^4 _2)He (^11 _5)B + (^1 _1)H \\\\rightarrow (^12 _6)C \\\\rightarrow 3 (^4 _2)He Atomic masses: ^11B = 11.00931, ^4He = 4.00260, ^1H = 1.00783.\",\"src\":\"stemez-PhysicalChemistry\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}