{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"cruxeval","formal_name":"CRUXEval","introduction":"CRUXEval takes 800 short Python functions and asks either for the output given an input (CRUXEval-O) or for an input that produces a given output (CRUXEval-I). It measures the ability to execute code mentally rather than to write it.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://crux-eval.github.io/","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"50b9b870-e7ec-5180-9290-3316c600d039","task_key":"default--test--sample~5f175","task_revision_id":"2","upstream_id":"sample_175","short_description":"'\\n', 2","config":"default","split":"test","body":"{\"code\":\"def f(s, amount):\\n    lines = s.splitlines()\\n    w = max(map(lambda l: l.rfind(' '), lines))\\n    ls = [[l, (w + 1) * amount - l.rfind(' ')] for l in lines]\\n    for i, line in enumerate(ls):\\n        ls[i][0] = line[0] + ' ' * line[1]\\n    return '\\\\n'.join(map(lambda l: l[0], ls))\",\"input\":\"'\\\\n', 2\"}","display_format":"code","language":"","answer_status":"published","assets":[],"source_url":"https://crux-eval.github.io/","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}