{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"omni-math","formal_name":"Omni-MATH","introduction":"Omni-MATH evaluates mathematical reasoning on Olympiad-level problems. Its official dataset contains 4,428 problems accompanied by domain and difficulty information.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"560b48a1-3191-578d-9cca-f734995b5245","task_key":"test--560b48a1-3191-578d-9cca-f734995b5245","task_revision_id":"1","upstream_id":"","short_description":"Determine all sequences $(x_1,x_2,\\ldots,x_{2011})$ of positive integers, such…","config":"","split":"test","body":"{\"problem\":\"Determine all sequences $(x_1,x_2,\\\\ldots,x_{2011})$ of positive integers, such that for every positive integer $n$ there exists an integer $a$ with \\\\[\\\\sum^{2011}_{j=1} j  x^n_j = a^{n+1} + 1\\\\]\\n\\n[i]\"}","display_format":"math","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}