{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"5a569ff1-14e3-5ed2-8492-ead3425e86a2","task_key":"default--test--12070","task_revision_id":"1","upstream_id":"12070","short_description":"A 5-kva transformer is supplying a lighting load; it would, in a normalday's…","config":"default","split":"test","body":"{\"category\":\"engineering\",\"options\":\"['75%', '90%', '80%', '68.5%']\",\"question\":\"A 5-kva transformer is supplying a lighting load; it would, in a normalday's run, operate at full load 1% hours and perhaps athalf load 1(1/2) hours?duringthe rest of the day there wouldbe no load on the transformer. The iron loss is 200 watts and the full-load copper loss (I^2R)is200 watts. Find the all-day efficiency of the transformer.\",\"src\":\"stemez-ElectricalMachines\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}