{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu","formal_name":"MMLU","introduction":"MMLU asks four-way multiple-choice questions across 57 subjects, from elementary material to professional-level examinations. Since 2020 it has been the most widely cited single reference point for general capability.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://github.com/hendrycks/test","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"663470df-6567-5d4c-b10b-08fcd9aef367","task_key":"all--test--663470df-6567-5d4c-b10b-08fcd9aef367","task_revision_id":"1","upstream_id":"","short_description":"Find $x$, given that\\[\\dfrac{\\sqrt{x}}{x\\sqrt{3}+\\sqrt{2}} =…","config":"all","split":"test","body":"{\"choices\":\"['\\\\\\\\frac{3}{4}', '\\\\\\\\frac{1}{4}', '\\\\\\\\frac{1}{2}', '\\\\\\\\frac{1}{8}']\",\"question\":\"Find $x$, given that\\\\[\\\\dfrac{\\\\sqrt{x}}{x\\\\sqrt{3}+\\\\sqrt{2}} = \\\\dfrac{1}{2x\\\\sqrt{6}+4}.\\\\]\",\"subject\":\"high_school_mathematics\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://github.com/hendrycks/test","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}