{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"6aba7479-6423-502d-b4f7-65d2e32a611b","task_key":"default--test--4580","task_revision_id":"1","upstream_id":"4580","short_description":"What is the standard free energy for the oxidation of glucose given by the…","config":"default","split":"test","body":"{\"category\":\"chemistry\",\"options\":\"['-300 kcal mole^-1', '-688 kcal mole^-1', '-57.0 kcal mole^-1', '-812 kcal mole^-1', '-474 kcal mole^-1', '-218 kcal mole^-1', '-540 kcal mole^-1', '-123 kcal mole^-1', '-350 kcal mole^-1', '-94.0 kcal mole^-1']\",\"question\":\"What is the standard free energy for the oxidation of glucose given by the reaction C_6H_12O_6(s) + 60_2(g) = 6CO_2(g) + 6H_2O(l)? The standard free energy of formation of C_6H_12O_6(s) = -218 kcal mole^-1, for CO_2(g), it is -94.0 kcal mole^-1 and for H_2O(l), it is -57.0 kcal mole^-1.\",\"src\":\"stemez-PhysicalChemistry\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}