{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"cruxeval","formal_name":"CRUXEval","introduction":"CRUXEval takes 800 short Python functions and asks either for the output given an input (CRUXEval-O) or for an input that produces a given output (CRUXEval-I). It measures the ability to execute code mentally rather than to write it.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://crux-eval.github.io/","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"7f1b3dff-04e7-56d6-9be4-5f251ca8d990","task_key":"default--test--sample~5f244","task_revision_id":"1","upstream_id":"sample_244","short_description":"'', 'BC1ty'","config":"default","split":"test","body":"{\"code\":\"def f(text, symbols):\\n    count = 0\\n    if symbols:\\n        for i in symbols:\\n            count += 1\\n        text = text * count\\n    return text.rjust(len(text) + count*2)[:-2]\",\"input\":\"'', 'BC1ty'\"}","display_format":"code","language":"","answer_status":"published","assets":[],"source_url":"https://crux-eval.github.io/","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}