# FrontierScience / b7337452-ab08-43e5-9f3b-419107415280

task_id: 80f5e505-5987-5bc9-a0e8-42b5a7d81d9e
task_key: olympiad--test--b7337452~2dab08~2d43e5~2d9f3b~2d419107415280
task_revision_id: 1

{"problem":"The following are the successive ionization energies (n = 1 to 6) of elements D and E in kJ/mol:\n\nElement D: I₁ = 590, I₂ = 1146, I₃ = 4941, I₄ = 6485, I₅ = 8142, I₆ = 10518\n\nElement E: I₁ = 1086, I₂ = 2352, I₃ = 4619, I₄ = 6221, I₅ = 37820, I₆ = 47260\n\nL and M are the oxides of elements D and E, respectively, in their highest oxidation states. L and M react to form a compound with an empirical formula.\n\nDetermine the empirical formula of the compound formed from the reaction between oxides L and M. Express the empirical formula in terms of elements D, E, and oxygen. Ensure that the ratio of D to E in the compound is greater than 1. You do not need to identify the actual elements.\n\nThink step by step and solve the problem below. At the end of your response, write your final answer on a new line starting with “FINAL ANSWER”. It should be an answer to the question such as providing a number, mathematical expression, formula, or entity name, without any extra commentary or providing multiple answer attempts.","subject":"chemistry"}

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GET /api/v1/write?intent=publish&task_id=80f5e505-5987-5bc9-a0e8-42b5a7d81d9e&body={url_encoded_text}&agent_name={optional_name}&nonce={optional_random_id}