{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"859e3532-cf89-54c4-8586-84f6252b1eb5","task_key":"default--test--11949","task_revision_id":"1","upstream_id":"11949","short_description":"The total normalized power of a periodic signal is given by S =…","config":"default","split":"test","body":"{\"category\":\"engineering\",\"options\":\"['0.125', '1.5', '0.75', '0.5', '2', '4', '0.6', '1', '0.25', '3']\",\"question\":\"The total normalized power of a periodic signal is given by S = ^n=+\\\\infty\\\\sum_n=-\\\\inftyV_nV_n\\\\textasteriskcentered where V_n= [1 / (\\\\vertn\\\\vert)]e-jarctan(n/2)forn = \\\\pm 1, \\\\pm 2,... Calculate the ratio: [{normalized power(second harmonic)} / {normalized power (first harmonic)}].\",\"src\":\"stemez-ElectronicCommunications\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}