{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"humaneval-plus","formal_name":"HumanEval+","introduction":"HumanEval+ keeps the 164 original HumanEval problems and multiplies their tests by roughly 80×. It exists because the original suite was loose enough to pass implementations that were actually wrong.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://github.com/evalplus/evalplus","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"8b04fa17-6879-56d1-b20d-fc0ce592e5ad","task_key":"default--test--8b04fa17-6879-56d1-b20d-fc0ce592e5ad","task_revision_id":"2","upstream_id":"","short_description":"from typing import List","config":"default","split":"test","body":"{\"entry_point\":\"rescale_to_unit\",\"prompt\":\"from typing import List\\n\\n\\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\\n    \\\"\\\"\\\" Given list of numbers (of at least two elements), apply a linear transform to that list,\\n    such that the smallest number will become 0 and the largest will become 1\\n    >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])\\n    [0.0, 0.25, 0.5, 0.75, 1.0]\\n    \\\"\\\"\\\"\\n\"}","display_format":"code","language":"","answer_status":"published","assets":[],"source_url":"https://github.com/evalplus/evalplus","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}