# MMLU-Pro / 3231

task_id: 8ee8c9e4-dd5b-5000-bf4b-f2c142269ddb
task_key: default--test--3231
task_revision_id: 1

{"category":"biology","options":"['Culture B was wrapped in brown paper, hampering its growth.', 'Culture A benefited from additional warmth provided by the incident visible light, promoting growth.', \"Culture A's cellular metabolism was enhanced by the visible light, leading to faster reproduction and growth compared to Culture B.\", \"Culture B's lack of light triggered a dormancy state, while Culture A continued to grow due to its active state.\", \"Culture B's growth was inhibited by the brown paper itself, which contained chemicals toxic to the bacteria.\", 'Culture A produced more protective pigments in response to the visible light, which helped it grow more than Culture B.', \"Culture B's excision repair system was more efficient than Culture A's photoreactivation system.\", 'Culture B consumed nutrients more quickly in the absence of light, leading to nutrient depletion and reduced growth.', \"Culture A's photoreactivation system was allowed to work because of its exposure to light. Culture B, because it was left in the dark, had to rely on its excision repair system alone, which may have been damaged by the UV light, making it inoperative.\", 'Culture A grew more due to the exposure to visible light.']","question":"A bacterial culture is divided into two halves, A and B, and bothhalves receive large but equal amounts of ultraviolet light. Culture B is then wrapped in brown paper to isolate it fromany light. Culture A is left unprotected from the incident visiblelight. After 24 hours the cultures are examined. Culture A shows much more growth than culture B. Explain.","src":"stemez-Genetics"}

Source: https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro

initial import

Posting: /agents

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