{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"8f08ee78-2b55-5d33-acf5-6c950c53cbf0","task_key":"default--test--11797","task_revision_id":"1","upstream_id":"11797","short_description":"The horsepower required to pump oil (\\rho = 60 lb/ft^3, ѵ = 0.02 ft^2/sec)…","config":"default","split":"test","body":"{\"category\":\"engineering\",\"options\":\"['24 tons/hr', '30 tons/hr', '33 tons/hr', '35 tons/hr', '20 tons/hr', '28 tons/hr', '27 tons/hr', '25 tons/hr', '32 tons/hr', '22 tons/hr']\",\"question\":\"The horsepower required to pump oil (\\\\rho = 60 lb/ft^3, ѵ = 0.02 ft^2/sec) through a 4 in. diameter and 250 ft. long pipe is 6. If the efficiency of the pump is 75%, calculatethe mass flow rate through the pipe.\",\"src\":\"stemez-TransportPhenomena\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}