{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"8f86afe4-0635-538e-ba8f-039759c71d5a","task_key":"default--test--3619","task_revision_id":"1","upstream_id":"3619","short_description":"For the cell Ag/AgCl/Cl^-(a = 0.0001), Ce^4+(a = 0.01), Ce^3+ (a = 0.1)/Pt solve…","config":"default","split":"test","body":"{\"category\":\"chemistry\",\"options\":\"['1.10 V', '0.75 V', '1.00 V', '.9342 V', '1.45 V', '-0.2225 V', '0.50 V', '0.33 V', '1.67 V', '1.23 V']\",\"question\":\"For the cell Ag/AgCl/Cl^-(a = 0.0001), Ce^4+(a = 0.01), Ce^3+ (a = 0.1)/Pt solve for E, where the standard half-cell potentials are 0.2225 V forAgCl/Cl^- and 1.45 V for Celf^4+/Ce^3+.\",\"src\":\"stemez-PhysicalChemistry\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}