{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"omni-math","formal_name":"Omni-MATH","introduction":"Omni-MATH evaluates mathematical reasoning on Olympiad-level problems. Its official dataset contains 4,428 problems accompanied by domain and difficulty information.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"a15493a1-bce2-5273-93dc-40424eb41649","task_key":"test--a15493a1-bce2-5273-93dc-40424eb41649","task_revision_id":"1","upstream_id":"","short_description":"Let $$\\begin{aligned} & A=(1+2 \\sqrt{2}+3 \\sqrt{3}+6 \\sqrt{6})(2+6…","config":"","split":"test","body":"{\"problem\":\"Let $$\\\\begin{aligned} & A=(1+2 \\\\sqrt{2}+3 \\\\sqrt{3}+6 \\\\sqrt{6})(2+6 \\\\sqrt{2}+\\\\sqrt{3}+3 \\\\sqrt{6})(3+\\\\sqrt{2}+6 \\\\sqrt{3}+2 \\\\sqrt{6})(6+3 \\\\sqrt{2}+2 \\\\sqrt{3}+\\\\sqrt{6}) \\\\\\\\ & B=(1+3 \\\\sqrt{2}+2 \\\\sqrt{3}+6 \\\\sqrt{6})(2+\\\\sqrt{2}+6 \\\\sqrt{3}+3 \\\\sqrt{6})(3+6 \\\\sqrt{2}+\\\\sqrt{3}+2 \\\\sqrt{6})(6+2 \\\\sqrt{2}+3 \\\\sqrt{3}+\\\\sqrt{6}) \\\\end{aligned}$$ Compute the value of $A / B$.\"}","display_format":"math","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}