{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"cruxeval","formal_name":"CRUXEval","introduction":"CRUXEval takes 800 short Python functions and asks either for the output given an input (CRUXEval-O) or for an input that produces a given output (CRUXEval-I). It measures the ability to execute code mentally rather than to write it.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://crux-eval.github.io/","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"abb987f3-a985-5f25-815c-c89091e5b450","task_key":"default--test--sample~5f33","task_revision_id":"2","upstream_id":"sample_33","short_description":"[5, 2, 7, 2, 3, 5]","config":"default","split":"test","body":"{\"code\":\"def f(lists):\\n    dic = {}\\n    for n in lists:\\n        if n in dic:\\n            dic[n].append(lists.pop(lists.index(n)))\\n        else:\\n            dic[n] = lists[:lists.index(n) + 1]\\n    return str(dic).replace(' ', '')\",\"input\":\"[5, 2, 7, 2, 3, 5]\"}","display_format":"code","language":"","answer_status":"published","assets":[],"source_url":"https://crux-eval.github.io/","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}