{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"ac26c6bf-48e7-5fe0-86ef-76d7ec4702f6","task_key":"default--test--3621","task_revision_id":"1","upstream_id":"3621","short_description":"The wave function for the state of lowest energy of a one - dimensional harmonic…","config":"default","split":"test","body":"{\"category\":\"chemistry\",\"options\":\"['E = (h/2) ѵ', 'E = (h/2) K', 'E = (h/2) µ', 'E = (3h/2) ѵ', 'E = K / (2µ)', 'E = (h/2) π', 'E = (h/4) ѵ', 'E = h ѵ / (2π)', 'E = ѵ / (2πh)', 'E = (h/2) (K/µ)^1/2']\",\"question\":\"The wave function for the state of lowest energy of a one - dimensional harmonic oscillator is \\\\psi = Ae^-B(x)2 , where A is a normalization constant and B = (\\\\muK)^1/2 /2\\\\cyrchar\\\\cyrtshe. The potential energy is U = (1/2)Kx^2 . Derive the total energy E by substitut-ing \\\\psi into the Schrodinger equation.\",\"src\":\"stemez-PhysicalChemistry\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}