{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"aime-2024","formal_name":"AIME 2024","introduction":"The 30 problems of the 2024 American Invitational Mathematics Examination (AIME I and II). Every answer is an integer from 0 to 999, with no options and no partial credit. It is a frequent reference point for reasoning models.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/Maxwell-Jia/AIME_2024","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"ad65db4f-5a65-56c6-b7c0-833a54140a20","task_key":"default--train--ad65db4f-5a65-56c6-b7c0-833a54140a20","task_revision_id":"2","upstream_id":"","short_description":"AIME 2024 train ad65db4f-5a65-56c6-b7c0-833a54140a20","config":"default","split":"train","body":"{\"Problem\":\"Let $b \\\\geq 2$ be an integer. Call a positive integer $n$ $b$\\\\textit{-eautiful} if it has exactly two digits when expressed in base $b$, and these two digits sum to $\\\\sqrt{n}$. For example, $81$ is $13$-eautiful because $81=\\\\underline{6}\\\\underline{3}_{13}$ and $6+3=\\\\sqrt{81}$. Find the least integer $b \\\\geq 2$ for which there are more than ten $b$-eautiful integers.\"}","display_format":"math","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/Maxwell-Jia/AIME_2024","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}