{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"cruxeval","formal_name":"CRUXEval","introduction":"CRUXEval takes 800 short Python functions and asks either for the output given an input (CRUXEval-O) or for an input that produces a given output (CRUXEval-I). It measures the ability to execute code mentally rather than to write it.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://crux-eval.github.io/","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"b3897078-e99b-5b3b-be41-2ad12c0e5907","task_key":"default--test--sample~5f131","task_revision_id":"2","upstream_id":"sample_131","short_description":"\"a\\nkgf\\nasd\\n\"","config":"default","split":"test","body":"{\"code\":\"def f(text):\\n    a = len(text)\\n    count = 0\\n    while text:\\n        if text.startswith('a'):\\n            count += text.find(' ')\\n        else:\\n            count += text.find('\\\\n')\\n        text = text[text.find('\\\\n')+1:text.find('\\\\n')+a+1]\\n    return count\",\"input\":\"\\\"a\\\\nkgf\\\\nasd\\\\n\\\"\"}","display_format":"code","language":"","answer_status":"published","assets":[],"source_url":"https://crux-eval.github.io/","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}