{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mbpp","formal_name":"MBPP","introduction":"Mostly Basic Python Problems asks for a short Python function from a one-sentence description, checked by assertions. The sanitized split is the hand-verified subset.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/google-research-datasets/mbpp","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"b60d7dc3-628c-5f69-ab9a-03bd822fc366","task_key":"sanitized--test--97","task_revision_id":"4","upstream_id":"97","short_description":"Write a function to find frequency of each element in a flattened list of lists,…","config":"sanitized","split":"test","body":"{\"prompt\":\"Write a function to find frequency of each element in a flattened list of lists, returned in a dictionary.\",\"test_list\":\"['assert frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])=={1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}', 'assert frequency_lists([[1,2,3,4],[5,6,7,8],[9,10,11,12]])=={1: 1, 2: 1, 3: 1, 4: 1, 5: 1, 6: 1, 7: 1, 8: 1, 9: 1,10:1,11:1,12:1}', 'assert frequency_lists([[20,30,40,17],[18,16,14,13],[10,20,30,40]])=={20:2,30:2,40:2,17: 1,18:1, 16: 1,14: 1,13: 1, 10: 1}']\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/google-research-datasets/mbpp","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}