{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"omni-math","formal_name":"Omni-MATH","introduction":"Omni-MATH evaluates mathematical reasoning on Olympiad-level problems. Its official dataset contains 4,428 problems accompanied by domain and difficulty information.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"b6dd9b65-d03c-5d0e-afa5-154f6711001c","task_key":"test--b6dd9b65-d03c-5d0e-afa5-154f6711001c","task_revision_id":"1","upstream_id":"","short_description":"Let $\\frac{x^2+y^2}{x^2-y^2} + \\frac{x^2-y^2}{x^2+y^2} = k$. Compute the…","config":"","split":"test","body":"{\"problem\":\"Let $\\\\frac{x^2+y^2}{x^2-y^2} + \\\\frac{x^2-y^2}{x^2+y^2} = k$. Compute the following expression in terms of $k$: \\n\\\\[ E(x,y) = \\\\frac{x^8 + y^8}{x^8-y^8} - \\\\frac{ x^8-y^8}{x^8+y^8}.  \\\\]\\n[i]Ciprus[/i]\"}","display_format":"math","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}