{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"b7be51b3-c7bc-5001-a965-a1d1d2e28b54","task_key":"default--test--11584","task_revision_id":"1","upstream_id":"11584","short_description":"The normal boiling point of water is 9720 cal/mole. Calculate the heat of…","config":"default","split":"test","body":"{\"category\":\"engineering\",\"options\":\"['650 cal/mole', '18.06 cal/mole', '9720 cal/mole', '9,850 cal/mole', '9,500 cal/mole', '12,150 cal/mole', '8,700 cal/mole', '10,750 cal/mole', '10,370 cal/mole', '11,000 cal/mole']\",\"question\":\"The normal boiling point of water is 9720 cal/mole. Calculate the heat of vaporization at 35°C and 1 atm. Use thefollowing C_p values to solve the problem. C_p Values forH_2O(1); C_p = 18.06 cal deg^-1 mole^-1 (independentof temperature) forH_2O(g); C_p = 7.219 + 2.374(10^-3)T + 2.67(10^-7)T^2 caldeg^-1 mole^-1\",\"src\":\"stemez-Thermodynamics\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}