{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"cruxeval","formal_name":"CRUXEval","introduction":"CRUXEval takes 800 short Python functions and asks either for the output given an input (CRUXEval-O) or for an input that produces a given output (CRUXEval-I). It measures the ability to execute code mentally rather than to write it.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://crux-eval.github.io/","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"bfde5131-750f-543b-958d-4e70c8496dbf","task_key":"default--test--sample~5f76","task_revision_id":"2","upstream_id":"sample_76","short_description":"[10, 3, 2, 2, 6, 0]","config":"default","split":"test","body":"{\"code\":\"def f(nums):\\n    nums = [y for y in nums if y > 0]\\n    if len(nums) <= 3:\\n        return nums\\n    nums.reverse()\\n    half = len(nums)//2\\n    return nums[:half] + [0]*5 + nums[half:]\",\"input\":\"[10, 3, 2, 2, 6, 0]\"}","display_format":"code","language":"","answer_status":"published","assets":[],"source_url":"https://crux-eval.github.io/","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}