{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"c7622906-4810-5988-88ed-ae91177fb6a1","task_key":"default--test--11718","task_revision_id":"1","upstream_id":"11718","short_description":"Evaluate the Laplace inverse of F(s) = [(5s 2 - 15s + 7) / {(s + 1)(s - 2)^3}]","config":"default","split":"test","body":"{\"category\":\"engineering\",\"options\":\"['- e^-t - e^2t + 2te^2t - (t^2 / 2)e^2t', 'e^-t - 2e^2t + 3te^2t - (t^3 / 6)e^2t', '-e^-t + 3e^2t - t^2e^2t', '-e^-t + 2e^2t - 2te^2t + (t^3 / 3)e^2t', 'e^-t + e^2t - 2te^2t + (t^2 / 2)e^2t', '-2e^-t - e^2t + (t^2 / 2)e^2t - te^2t', 'e^-t + e^2t - (t^2 / 2)e^2t - 3te^2t', '2e^-t + 3e^2t - 4te^2t + (t^3 / 3)e^2t', '- e^-t + e^2t + 2te^2t - (t^2 / 2)e^2t', '- e^-t + e^2t - 2te^2t + (t^2 / 2)e^2t']\",\"question\":\"Evaluate the Laplace inverse of F(s) = [(5s 2 - 15s + 7) / {(s + 1)(s - 2)^3}]\",\"src\":\"stemez-ElectronicCommunications\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}