{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"d2d0055f-dc53-595a-9fa8-273302d66b14","task_key":"default--test--11427","task_revision_id":"1","upstream_id":"11427","short_description":"Find the Fourier cosine series over the interval 0 < x < c for the function f(x)…","config":"default","split":"test","body":"{\"category\":\"engineering\",\"options\":\"['f(x) \\\\\\\\sim (1 / 2)c + (2c / \\\\\\\\pi^2)\\\\\\\\infty\\\\\\\\sum_k=1 [{cos[(2k)\\\\\\\\pix/ c]} / (2k)^2]', 'f(x) \\\\\\\\sim (1 / 2)c + (4c / \\\\\\\\pi^2)\\\\\\\\infty\\\\\\\\sum_k=0 [{cos[(2k + 1)\\\\\\\\pix/ c]} / (2k + 1)^2]', 'f(x) \\\\\\\\sim (1 / 2)c - (4c / \\\\\\\\pi^2)\\\\\\\\infty\\\\\\\\sum_n=1 [1 / n^2]cos{(n\\\\\\\\pix) / c}', 'f(x) \\\\\\\\sim (1 / 2)c - (4c / \\\\\\\\pi^2)\\\\\\\\infty\\\\\\\\sum_k=0 [{cos[(2k + 1)\\\\\\\\pix/ c]} / (2k + 1)^2]', 'f(x) \\\\\\\\sim (1 / 2)c - (4c / \\\\\\\\pi^2)\\\\\\\\infty\\\\\\\\sum_k=1 [{cos[(2k)\\\\\\\\pix/ c]} / (2k)^2]', 'f(x) \\\\\\\\sim (1 / 2)c - (2c / \\\\\\\\pi^2)\\\\\\\\infty\\\\\\\\sum_n=0 [{1 - (-1)^n} / n^2]cos{(n\\\\\\\\pix) / c}', 'f(x) \\\\\\\\sim (1 / 2)c + (4c / \\\\\\\\pi^2)\\\\\\\\infty\\\\\\\\sum_n=1 [{(-1)^n} / n^2]cos{(n\\\\\\\\pix) / c}', 'f(x) \\\\\\\\sim (1 / 2)c + (2c / \\\\\\\\pi^2)\\\\\\\\infty\\\\\\\\sum_n=1 [{1 - (- 1)^n} / n^2]cos{(n\\\\\\\\pix) / c}', 'f(x) \\\\\\\\sim (1 / 2)c + (2c / \\\\\\\\pi^2)\\\\\\\\infty\\\\\\\\sum_n=1 [(-1)^n / n^2]cos{(n\\\\\\\\pix) / c}', 'f(x) \\\\\\\\sim (1 / 2)c - (2c / \\\\\\\\pi^2)\\\\\\\\infty\\\\\\\\sum_n=1 [{1 - (- 1)^n} / n^2]cos{(n\\\\\\\\pix) / c}']\",\"question\":\"Find the Fourier cosine series over the interval 0 < x < c for the function f(x) = x.\",\"src\":\"stemez-ElectronicCommunications\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}