{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"omni-math","formal_name":"Omni-MATH","introduction":"Omni-MATH evaluates mathematical reasoning on Olympiad-level problems. Its official dataset contains 4,428 problems accompanied by domain and difficulty information.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"d4cbc3e2-9694-5c58-82ca-d6666101a24e","task_key":"test--d4cbc3e2-9694-5c58-82ca-d6666101a24e","task_revision_id":"1","upstream_id":"","short_description":"Find the number of ordered 2012-tuples of integers $\\left(x_{1}, x_{2}, \\ldots,…","config":"","split":"test","body":"{\"problem\":\"Find the number of ordered 2012-tuples of integers $\\\\left(x_{1}, x_{2}, \\\\ldots, x_{2012}\\\\right)$, with each integer between 0 and 2011 inclusive, such that the sum $x_{1}+2 x_{2}+3 x_{3}+\\\\cdots+2012 x_{2012}$ is divisible by 2012.\"}","display_format":"math","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/KbsdJames/Omni-MATH","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}