{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"d7fe285b-1814-5e5d-a64e-93aec6550137","task_key":"default--test--4493","task_revision_id":"1","upstream_id":"4493","short_description":"A solution made up of 150 grams of benzene and 25.1 grams of a solute has a…","config":"default","split":"test","body":"{\"category\":\"chemistry\",\"options\":\"['120 g solute/mole solute', '95 g solute/mole solute', '110 g solute/mole solute', '130 g solute/mole solute', '100 g solute/mole solute', '105 g solute/mole solute', '125 g solute/mole solute', '150 g solute/mole solute', '115 g solute/mole solute', '140 g solute/mole solute']\",\"question\":\"A solution made up of 150 grams of benzene and 25.1 grams of a solute has a freezing point of - 1.92°C. The freezing point of pure benzene is 5.50°C and themolal freezing point constant is 5.10. Determine the approximate molar weight of the solute.\",\"src\":\"stemez-PhysicalChemistry\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}