{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"da7a5208-26a3-5953-b6cf-709937ffe4f4","task_key":"default--test--11349","task_revision_id":"1","upstream_id":"11349","short_description":"Find the inverse Laplace transform L^-1[1 / {s(s^2 + 4)}], using the…","config":"default","split":"test","body":"{\"category\":\"engineering\",\"options\":\"['(1 / 2)(e^(2t) - 1)', '(1 / 2)(1 + cos2t)', '(1 / 4)(1 - cos2t)', '(1 / 4)(sin(2t) - cos(2t))', '(1 / 2)sin(2t)', 'e^(-2t) * sin(2t)', '(1 / 2)(1 - cos2t)', 't * sin(2t)', '(1 / 4)(1 + cos2t)', 'sin(2t)']\",\"question\":\"Find the inverse Laplace transform L^-1[1 / {s(s^2 + 4)}], using the convolution.\",\"src\":\"stemez-ElectronicCommunications\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}