{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"ea0a64cf-ed00-5f90-9e10-82356b98a2ff","task_key":"default--test--10095","task_revision_id":"1","upstream_id":"10095","short_description":"The acceleration of the mass of a spring-mass system is given as a function of…","config":"default","split":"test","body":"{\"category\":\"physics\",\"options\":\"['v^2 = (\\\\nho - x^2) (k/m)', 'v^2 = (\\\\nho^2 + x^2) (k/m)', 'v = √((ρ^2 / x) (k/m))', 'v^2 = (ρ^2 * x^2) (k/m)', 'v = √((ρ + x^2) (k/m))', 'v^2 = (\\\\nho^2 - x^2) (k/m)', 'v^2 = (2ρ^2 - x^2) (k/m)', 'v^2 = ρ(k/m) - x^2', 'v^2 = (ρ^2 + 2x^2) (k/m)', 'v^2 = (\\\\nho^2 - x) (k/m)']\",\"question\":\"The acceleration of the mass of a spring-mass system is given as a function of the displacement: a (x) = - (k/m)x. If the mass is started from rest at a displacement of - \\\\rho determine the velocity of the mass as a function of the displacement.\",\"src\":\"stemez-Mechanics\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}