{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"bbeh","formal_name":"BIG-Bench Extra Hard (BBEH)","introduction":"BIG-Bench Extra Hard evaluates language-model reasoning through challenging task categories. It offers full and mini distributions; this import contains the full distribution: 4,520 questions across all 23 task categories.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://github.com/google-deepmind/bbeh","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"ebbf3cd1-023d-5bed-bdd5-1640a9d2df18","task_key":"bbeh~5fword~5fsorting--full--ebbf3cd1-023d-5bed-bdd5-1640a9d2df18","task_revision_id":"1","upstream_id":"","short_description":"You are an expert in word sorting. You will be provided with a list of words and…","config":"bbeh_word_sorting","split":"full","body":"{\"input\":\"\\nYou are an expert in word sorting. You will be provided with a list of words and the steps taken, in the form of thoughts, to arrange them in alphabetical order.\\nYour job is to identify the first step that was a mistake in reasoning about the order of the words. This can be misunderstanding the order of\\nthe alphabet or getting the word or letter wrong or missing a word entirely.\\nQ: Sort the following words alphabetically: List: ackerman rare nowadays photolytic cypriot seaborg liaison cent burnout pronto hetman taipei protophyta ferruginous sierra arctic trinket rivet punitive splotch\\nThought 1: I should start by looking at the first letter of the words in the list. The first letter: \\\"ackerman\\\": \\\"a\\\" (1). \\\"rare\\\": \\\"r\\\" (18). \\\"nowadays\\\": \\\"n\\\" (14). \\\"photolytic\\\": \\\"p\\\" (16). \\\"cypriot\\\": \\\"c\\\" (3). \\\"seaborg\\\": \\\"s\\\" (19). \\\"liaison\\\": \\\"l\\\" (12). \\\"cent\\\": \\\"c\\\" (3). \\\"burnout\\\": \\\"b\\\" (2). \\\"pronto\\\": \\\"p\\\" (16). \\\"hetman\\\": \\\"h\\\" (8). \\\"taipei\\\": \\\"t\\\" (20). \\\"protophyta\\\": \\\"p\\\" (16). \\\"ferruginous\\\": \\\"f\\\" (6). \\\"sierra\\\": \\\"s\\\" (19). \\\"arctic\\\": \\\"a\\\" (1). \\\"trinket\\\": \\\"t\\\" (20). \\\"rivet\\\": \\\"r\\\" (18). \\\"punitive\\\": \\\"p\\\" (16). \\\"splotch\\\": \\\"s\\\" (19).\\nThought 2: We now have: (1) [\\\"ackerman\\\" ? \\\"arctic\\\"] < (2) \\\"burnout\\\" < (3) [\\\"cent\\\" ? \\\"cypriot\\\" ? \\\"liaison\\\"] < (6) \\\"ferruginous\\\" < (8) \\\"hetman\\\" < (12) \\\"liaison\\\" < (14) \\\"nowadays\\\" < (16) [\\\"photolytic\\\" ? \\\"pronto\\\" ? \\\"protophyta\\\" ? \\\"punitive\\\"] < (18) [\\\"rare\\\" ? \\\"rivet\\\"] < (19) [\\\"seaborg\\\" ? \\\"sierra\\\" ? \\\"splotch\\\"] < (20) [\\\"taipei\\\" ? \\\"trinket\\\"].\\nThought 3: Now let's sort this subpart [\\\"ackerman\\\" ? \\\"arctic\\\"] by looking at their second letters. The second letter: \\\"ackerman\\\": \\\"c\\\" (3). \\\"arctic\\\": \\\"r\\\" (18).\\nThought 4: We now have: (3) \\\"ackerman\\\" < (18) \\\"arctic\\\" for the subpart. Hence, we have \\\"ackerman\\\" < \\\"arctic\\\" < \\\"burnout\\\" < [\\\"cent\\\" ? \\\"cypriot\\\" ? \\\"liaison\\\"] < \\\"ferruginous\\\" < \\\"hetman\\\" < \\\"liaison\\\" < \\\"nowadays\\\" < [\\\"photolytic\\\" ? \\\"pronto\\\" ? \\\"protophyta\\\" ? \\\"punitive\\\"] < [\\\"rare\\\" ? \\\"rivet\\\"] < [\\\"seaborg\\\" ? \\\"sierra\\\" ? \\\"splotch\\\"] < [\\\"taipei\\\" ? \\\"trinket\\\"].\\nThought 5: Now let's sort this subpart [\\\"cent\\\" ? \\\"cypriot\\\" ? \\\"liaison\\\"] by looking at their second letters. The second letter: \\\"cent\\\": \\\"e\\\" (5). \\\"cypriot\\\": \\\"y\\\" (25). \\\"liaison\\\": \\\"i\\\" (9).\\nThought 6: We now have: (5) \\\"cent\\\" < (9) \\\"liaison\\\" < (25) \\\"cypriot\\\" for the subpart. Hence, we have \\\"ackerman\\\" < \\\"arctic\\\" < \\\"burnout\\\" < \\\"cent\\\" < \\\"liaison\\\" < \\\"cypriot\\\" < \\\"ferruginous\\\" < \\\"hetman\\\" < \\\"liaison\\\" < \\\"nowadays\\\" < [\\\"photolytic\\\" ? \\\"pronto\\\" ? \\\"protophyta\\\" ? \\\"punitive\\\"] < [\\\"rare\\\" ? \\\"rivet\\\"] < [\\\"seaborg\\\" ? \\\"sierra\\\" ? \\\"splotch\\\"] < [\\\"taipei\\\" ? \\\"trinket\\\"].\\nThought 7: Now let's sort this subpart [\\\"photolytic\\\" ? \\\"pronto\\\" ? \\\"protophyta\\\" ? \\\"punitive\\\"] by looking at their second letters. The second letter: \\\"photolytic\\\": \\\"h\\\" (8). \\\"pronto\\\": \\\"r\\\" (18). \\\"protophyta\\\": \\\"r\\\" (18). \\\"punitive\\\": \\\"u\\\" (21).\\nThought 8: We now have: (8) \\\"photolytic\\\" < (18) [\\\"pronto\\\" ? \\\"protophyta\\\"] < (21) \\\"punitive\\\" for the subpart. Hence, we have \\\"ackerman\\\" < \\\"arctic\\\" < \\\"burnout\\\" < \\\"cent\\\" < \\\"liaison\\\" < \\\"cypriot\\\" < \\\"ferruginous\\\" < \\\"hetman\\\" < \\\"liaison\\\" < \\\"nowadays\\\" < \\\"photolytic\\\" < [\\\"pronto\\\" ? \\\"protophyta\\\"] < [\\\"rare\\\" ? \\\"rivet\\\"] < [\\\"seaborg\\\" ? \\\"sierra\\\" ? \\\"splotch\\\"] < [\\\"taipei\\\" ? \\\"trinket\\\"].\\nThought 9: Now let's sort this subpart [\\\"pronto\\\" ? \\\"protophyta\\\"] by looking at their third letters. The third letter: \\\"pronto\\\": \\\"n\\\" (14). \\\"protophyta\\\": \\\"t\\\" (20).\\nThought 10: We now have: (14) \\\"pronto\\\" < (20) \\\"protophyta\\\" for the subpart. Hence, we have \\\"ackerman\\\" < \\\"arctic\\\" < \\\"burnout\\\" < \\\"cent\\\" < \\\"liaison\\\" < \\\"cypriot\\\" < \\\"ferruginous\\\" < \\\"hetman\\\" < \\\"liaison\\\" < \\\"nowadays\\\" < \\\"photolytic\\\" < \\\"pronto\\\" < \\\"protophyta\\\" < [\\\"rare\\\" ? \\\"rivet\\\"] < [\\\"seaborg\\\" ? \\\"sierra\\\" ? \\\"splotch\\\"] < [\\\"taipei\\\" ? \\\"trinket\\\"].\\nThought 11: Now let's sort this subpart [\\\"rare\\\" ? \\\"rivet\\\"] by looking at their second letters. The second letter: \\\"rare\\\": \\\"a\\\" (1). \\\"rivet\\\": \\\"i\\\" (9).\\nThought 12: We now have: (1) \\\"rare\\\" < (9) \\\"rivet\\\" for the subpart. Hence, we have \\\"ackerman\\\" < \\\"arctic\\\" < \\\"burnout\\\" < \\\"cent\\\" < \\\"liaison\\\" < \\\"cypriot\\\" < \\\"ferruginous\\\" < \\\"hetman\\\" < \\\"liaison\\\" < \\\"nowadays\\\" < \\\"photolytic\\\" < \\\"pronto\\\" < \\\"protophyta\\\" < \\\"rare\\\" < \\\"rivet\\\" < [\\\"seaborg\\\" ? \\\"sierra\\\" ? \\\"splotch\\\"] < [\\\"taipei\\\" ? \\\"trinket\\\"].\\nThought 13: Now let's sort this subpart [\\\"seaborg\\\" ? \\\"sierra\\\" ? \\\"splotch\\\"] by looking at their second letters. The second letter: \\\"seaborg\\\": \\\"e\\\" (5). \\\"sierra\\\": \\\"i\\\" (9). \\\"splotch\\\": \\\"p\\\" (16).\\nThought 14: We now have: (5) \\\"seaborg\\\" < (9) \\\"sierra\\\" < (16) \\\"splotch\\\" for the subpart. Hence, we have \\\"ackerman\\\" < \\\"arctic\\\" < \\\"burnout\\\" < \\\"cent\\\" < \\\"liaison\\\" < \\\"cypriot\\\" < \\\"ferruginous\\\" < \\\"hetman\\\" < \\\"liaison\\\" < \\\"nowadays\\\" < \\\"photolytic\\\" < \\\"pronto\\\" < \\\"protophyta\\\" < \\\"rare\\\" < \\\"rivet\\\" < \\\"seaborg\\\" < \\\"sierra\\\" < \\\"splotch\\\" < [\\\"taipei\\\" ? \\\"trinket\\\"].\\nThought 15: Now let's sort this subpart [\\\"taipei\\\" ? \\\"trinket\\\"] by looking at their second letters. The second letter: \\\"taipei\\\": \\\"a\\\" (1). \\\"trinket\\\": \\\"r\\\" (18).\\nThought 16: We now have: (1) \\\"taipei\\\" < (18) \\\"trinket\\\" for the subpart. Hence, we have \\\"ackerman\\\" < \\\"arctic\\\" < \\\"burnout\\\" < \\\"cent\\\" < \\\"liaison\\\" < \\\"cypriot\\\" < \\\"ferruginous\\\" < \\\"hetman\\\" < \\\"liaison\\\" < \\\"nowadays\\\" < \\\"photolytic\\\" < \\\"pronto\\\" < \\\"protophyta\\\" < \\\"rare\\\" < \\\"rivet\\\" < \\\"seaborg\\\" < \\\"sierra\\\" < \\\"splotch\\\" < \\\"taipei\\\" < \\\"trinket\\\".\\nThought 17: I have now sorted all the words. The answer is nowadays, photolytic, cypriot, seaborg, liaison, cent, burnout, pronto, hetman, taipei, protophyta, ferruginous, sierra, arctic, trinket, rivet, punitive, splotch, ackerman, rare\\nQ: Is there a mistake in this sequence? Write \\\"No\\\" if there are no mistakes, or the number N if there is a mistake in Thought N.\\n\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://github.com/google-deepmind/bbeh","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}