{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"ebc25faa-e6f6-5e7e-be7a-2e597e39a354","task_key":"default--test--7844","task_revision_id":"1","upstream_id":"7844","short_description":"The height (in meters) of a shot cannonball follows a trajectory given by $h(t)…","config":"default","split":"test","body":"{\"category\":\"math\",\"options\":\"['\\\\\\\\frac{5}{12}', '\\\\\\\\frac{7}{14}', '\\\\\\\\frac{14}{7}', '\\\\\\\\frac{12}{7}', '\\\\\\\\frac{5}{7}', '\\\\\\\\frac{6}{7}', '\\\\\\\\frac{7}{5}', '\\\\\\\\frac{9}{7}', '\\\\\\\\frac{7}{12}', '\\\\\\\\frac{8}{7}']\",\"question\":\"The height (in meters) of a shot cannonball follows a trajectory given by $h(t) = -4.9t^2 + 14t - 0.4$ at time $t$ (in seconds). As an improper fraction, for how long is the cannonball above a height of $6$ meters?\",\"src\":\"ori_mmlu-high_school_mathematics\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}