{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"f1c98897-12df-5fb2-8cc1-46d749e77f6a","task_key":"default--test--10249","task_revision_id":"1","upstream_id":"10249","short_description":"The position of an object is given by the equations x = 2.0t^3 + 4.0t + 6.25,…","config":"default","split":"test","body":"{\"category\":\"physics\",\"options\":\"['9 m/s^2', '12 m/s^2', '21 m/s^2', '6 m/s^2', '15 m/s^2', '30 m/s^2', '36 m/s^2', '24 m/s^2', '3 m/s^2', '18 m/s^2']\",\"question\":\"The position of an object is given by the equations x = 2.0t^3 + 4.0t + 6.25, where x is in meters and t is in seconds. What is the acceleration of the object at t = 1.50 s?\",\"src\":\"ori_mmlu-high_school_physics\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}