{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"f6019bcb-4aa3-5193-a431-efc254d09b9b","task_key":"default--test--11677","task_revision_id":"1","upstream_id":"11677","short_description":"Calculate the safe thickness of the shield coating necessary ona radioactive…","config":"default","split":"test","body":"{\"category\":\"engineering\",\"options\":\"['4 ft', '3 ft or 36 in', '1.5 ft or 18 in', '0.5 ft', '0.1 ft or 1.2 in', '0.75 ft or 9 in', '0.25 ft or 3 in', '0.05 ft or 0.6 in', '1 ft', '2 ft']\",\"question\":\"Calculate the safe thickness of the shield coating necessary ona radioactive waste spherical ball of 1 ft. radius to be dumpedin the ocean with ambient water temperature of 50°F.The waste ball gives off heat at the rate of 440 Btu/hr. The thermal conductivity of the shielding material is k = 0.02 Btu/hrft°F.\",\"src\":\"stemez-HeatTransfer\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}