{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"cruxeval","formal_name":"CRUXEval","introduction":"CRUXEval takes 800 short Python functions and asks either for the output given an input (CRUXEval-O) or for an input that produces a given output (CRUXEval-I). It measures the ability to execute code mentally rather than to write it.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://crux-eval.github.io/","indexing_mode":"noindex","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[]}},"task_id":"f76f573c-e498-57d5-8a03-0b8cb9e2350c","task_key":"default--test--sample~5f184","task_revision_id":"2","upstream_id":"sample_184","short_description":"[1,2]","config":"default","split":"test","body":"{\"code\":\"def f(digits):\\n    digits.reverse()\\n    if len(digits) < 2:\\n        return digits\\n    for i in range(0, len(digits), 2):\\n        digits[i], digits[i+1] = digits[i+1], digits[i]\\n    return digits\",\"input\":\"[1,2]\"}","display_format":"code","language":"","answer_status":"published","assets":[],"source_url":"https://crux-eval.github.io/","history":"initial import","indexing_mode":"noindex","subproblems":[],"grids":[]}