{"kind":"task","effective_mode":"full","benchmark":{"kind":"benchmark","effective_mode":"full","slug":"mmlu-pro","formal_name":"MMLU-Pro","introduction":"MMLU-Pro rebuilds MMLU with ten answer options instead of four and removes items that no longer separate models. Questions span fourteen academic and professional subjects.","introduction_ja":"","introduction_en":"","category":"Category not supplied","task_count":null,"acquisition_status":"Acquisition status not supplied","official_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","indexing_mode":"index","profile":{"resources":[],"task_format":"","scoring":"","metric":"","size":"","answer_access":"","license":"","citation":"","maintainer":"","released":"","why_hard":"","related":[],"history":"","construction":"","limitations":"","saturation":"","scores":[]}},"task_id":"face05c0-3c27-544a-9558-b4a1420ce677","task_key":"default--test--4588","task_revision_id":"1","upstream_id":"4588","short_description":"The isomer of C_2H_5OH(l) is CH_3 - O - CH_3(g) . Given that, at 25°C, the heat…","config":"default","split":"test","body":"{\"category\":\"chemistry\",\"options\":\"['\\\\\\\\DeltaH = 22 kcal, \\\\\\\\DeltaE = - 10.6 kcal', '\\\\\\\\DeltaH = 204 kcal, \\\\\\\\DeltaE = - 204 kcal', '\\\\\\\\DeltaH = 204 kcal, \\\\\\\\DeltaE = 204 kcal', '\\\\\\\\DeltaH = 348 kcal, \\\\\\\\DeltaE = - 188 kcal', '\\\\\\\\DeltaH = 66 kcal, \\\\\\\\DeltaE = - 10 kcal', '\\\\\\\\DeltaH = -66 kcal, \\\\\\\\DeltaE = -10 kcal', '\\\\\\\\DeltaH = 66 kcal, \\\\\\\\DeltaE = 10 kcal', '\\\\\\\\DeltaH = -22 kcal, \\\\\\\\DeltaE = 10.6 kcal', '\\\\\\\\DeltaH = -348 kcal, \\\\\\\\DeltaE = 188 kcal', '\\\\\\\\DeltaH = 348 kcal, \\\\\\\\DeltaE = 10 kcal']\",\"question\":\"The isomer of C_2H_5OH(l) is CH_3 - O - CH_3(g) . Given that, at 25°C, the heat of formation of C_2H_5OH(l) = - 66 kcal/mole, the heat of combustion of the isomeric CH_3 - O - CH_3(g) to CO_2(g) and H_2O(l) = - 348 kcal/mole, the heat of formation of H_2O(l) = - 68 kcal/mole and the heat of combustion of carbon to CO_2(g) = - 94 kcal/mole. Calculate a) \\\\DeltaH_298°K for the reaction and b) \\\\DeltaE_298°K for the reaction assuming \\\\DeltaH_298°K in part a) = - 10 kcal.\",\"src\":\"stemez-PhysicalChemistry\"}","display_format":"text","language":"","answer_status":"published","assets":[],"source_url":"https://huggingface.co/datasets/TIGER-Lab/MMLU-Pro","history":"initial import","indexing_mode":"index","subproblems":[],"grids":[]}